Base | Representation |
---|---|
bin | 11110000101101110100100… |
… | …111110001001101111110111 |
3 | 122100120002210001002011121002 |
4 | 132011232210332021233313 |
5 | 114321134042302111320 |
6 | 1145241510113113515 |
7 | 36605613535533203 |
oct | 3605564476115767 |
9 | 570502701064532 |
10 | 132335005113335 |
11 | 39190a62469042 |
12 | 12a134b155889b |
13 | 58ac1a2c3c36b |
14 | 2497096c2bb03 |
15 | 104750ce75675 |
hex | 785ba4f89bf7 |
132335005113335 has 16 divisors (see below), whose sum is σ = 159536795443200. Its totient is φ = 105378535364256.
The previous prime is 132335005113331. The next prime is 132335005113419. The reversal of 132335005113335 is 533311500533231.
It is a cyclic number.
It is not a de Polignac number, because 132335005113335 - 22 = 132335005113331 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132335005113331) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 21715415 + ... + 27133544.
It is an arithmetic number, because the mean of its divisors is an integer number (9971049715200).
Almost surely, 2132335005113335 is an apocalyptic number.
132335005113335 is a deficient number, since it is larger than the sum of its proper divisors (27201790329865).
132335005113335 is a wasteful number, since it uses less digits than its factorization.
132335005113335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 48851470.
The product of its (nonzero) digits is 182250, while the sum is 38.
Adding to 132335005113335 its reverse (533311500533231), we get a palindrome (665646505646566).
The spelling of 132335005113335 in words is "one hundred thirty-two trillion, three hundred thirty-five billion, five million, one hundred thirteen thousand, three hundred thirty-five".
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