Base | Representation |
---|---|
bin | 11110000101101110100100… |
… | …111110001001101111110011 |
3 | 122100120002210001002011120221 |
4 | 132011232210332021233303 |
5 | 114321134042302111311 |
6 | 1145241510113113511 |
7 | 36605613535533166 |
oct | 3605564476115763 |
9 | 570502701064527 |
10 | 132335005113331 |
11 | 39190a62469039 |
12 | 12a134b1558897 |
13 | 58ac1a2c3c367 |
14 | 2497096c2badd |
15 | 104750ce75671 |
hex | 785ba4f89bf3 |
132335005113331 has 2 divisors, whose sum is σ = 132335005113332. Its totient is φ = 132335005113330.
The previous prime is 132335005113329. The next prime is 132335005113419. The reversal of 132335005113331 is 133311500533231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132335005113331 - 21 = 132335005113329 is a prime.
It is a super-2 number, since 2×1323350051133312 (a number of 29 digits) contains 22 as substring.
Together with 132335005113329, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (132335005113301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66167502556665 + 66167502556666.
It is an arithmetic number, because the mean of its divisors is an integer number (66167502556666).
Almost surely, 2132335005113331 is an apocalyptic number.
132335005113331 is a deficient number, since it is larger than the sum of its proper divisors (1).
132335005113331 is an equidigital number, since it uses as much as digits as its factorization.
132335005113331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36450, while the sum is 34.
Adding to 132335005113331 its reverse (133311500533231), we get a palindrome (265646505646562).
The spelling of 132335005113331 in words is "one hundred thirty-two trillion, three hundred thirty-five billion, five million, one hundred thirteen thousand, three hundred thirty-one".
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