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132340001231717 is a prime number
BaseRepresentation
bin11110000101110011001110…
…110000110101001101100101
3122100120120200020011021120122
4132011303032300311031211
5114321224310303403332
61145244053545211325
736606151413043046
oct3605631660651545
9570516606137518
10132340001231717
11391930966647a4
1212a14466790b45
1358ac7bb03c226
14249740c59c8cd
1510477018b1c12
hex785ccec35365

132340001231717 has 2 divisors, whose sum is σ = 132340001231718. Its totient is φ = 132340001231716.

The previous prime is 132340001231681. The next prime is 132340001231729. The reversal of 132340001231717 is 717132100043231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 68214483750436 + 64125517481281 = 8259206^2 + 8007841^2 .

It is a cyclic number.

It is not a de Polignac number, because 132340001231717 - 26 = 132340001231653 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132340001231017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66170000615858 + 66170000615859.

It is an arithmetic number, because the mean of its divisors is an integer number (66170000615859).

Almost surely, 2132340001231717 is an apocalyptic number.

It is an amenable number.

132340001231717 is a deficient number, since it is larger than the sum of its proper divisors (1).

132340001231717 is an equidigital number, since it uses as much as digits as its factorization.

132340001231717 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 21168, while the sum is 35.

Adding to 132340001231717 its reverse (717132100043231), we get a palindrome (849472101274948).

The spelling of 132340001231717 in words is "one hundred thirty-two trillion, three hundred forty billion, one million, two hundred thirty-one thousand, seven hundred seventeen".