Base | Representation |
---|---|
bin | 111101101000010111… |
… | …1000001011101011001 |
3 | 110122121202202202022121 |
4 | 1323100233001131121 |
5 | 4132023324202203 |
6 | 140445021221241 |
7 | 12363531664603 |
oct | 1732057013531 |
9 | 418552682277 |
10 | 132351006553 |
11 | 51147769157 |
12 | 21798101821 |
13 | c632c9827c |
14 | 6597814173 |
15 | 369945d0bd |
hex | 1ed0bc1759 |
132351006553 has 2 divisors, whose sum is σ = 132351006554. Its totient is φ = 132351006552.
The previous prime is 132351006527. The next prime is 132351006617. The reversal of 132351006553 is 355600153231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 104124318489 + 28226688064 = 322683^2 + 168008^2 .
It is an emirp because it is prime and its reverse (355600153231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 132351006553 - 221 = 132348909401 is a prime.
It is not a weakly prime, because it can be changed into another prime (132351066553) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66175503276 + 66175503277.
It is an arithmetic number, because the mean of its divisors is an integer number (66175503277).
Almost surely, 2132351006553 is an apocalyptic number.
It is an amenable number.
132351006553 is a deficient number, since it is larger than the sum of its proper divisors (1).
132351006553 is an equidigital number, since it uses as much as digits as its factorization.
132351006553 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40500, while the sum is 34.
Adding to 132351006553 its reverse (355600153231), we get a palindrome (487951159784).
The spelling of 132351006553 in words is "one hundred thirty-two billion, three hundred fifty-one million, six thousand, five hundred fifty-three".
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