Base | Representation |
---|---|
bin | 11000101001101111… |
… | …11101000101110001 |
3 | 1021011101012110201111 |
4 | 30110313331011301 |
5 | 204101142124403 |
6 | 10025150233321 |
7 | 645656421136 |
oct | 142467750561 |
9 | 37141173644 |
10 | 13235114353 |
11 | 568197133a |
12 | 26944b5841 |
13 | 132c001b16 |
14 | 8d7a8c58d |
15 | 526de556d |
hex | 314dfd171 |
13235114353 has 2 divisors, whose sum is σ = 13235114354. Its totient is φ = 13235114352.
The previous prime is 13235114327. The next prime is 13235114369. The reversal of 13235114353 is 35341153231.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11373795904 + 1861318449 = 106648^2 + 43143^2 .
It is a cyclic number.
It is not a de Polignac number, because 13235114353 - 233 = 4645179761 is a prime.
It is not a weakly prime, because it can be changed into another prime (13235114383) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6617557176 + 6617557177.
It is an arithmetic number, because the mean of its divisors is an integer number (6617557177).
Almost surely, 213235114353 is an apocalyptic number.
It is an amenable number.
13235114353 is a deficient number, since it is larger than the sum of its proper divisors (1).
13235114353 is an equidigital number, since it uses as much as digits as its factorization.
13235114353 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 16200, while the sum is 31.
Adding to 13235114353 its reverse (35341153231), we get a palindrome (48576267584).
The spelling of 13235114353 in words is "thirteen billion, two hundred thirty-five million, one hundred fourteen thousand, three hundred fifty-three".
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