Base | Representation |
---|---|
bin | 1100000010011000101010… |
… | …1100010101000010101101 |
3 | 1201212021011100100201200101 |
4 | 3000212022230111002231 |
5 | 3213321012001142214 |
6 | 44052044122031101 |
7 | 2534130432166522 |
oct | 300461254250255 |
9 | 51767140321611 |
10 | 13235121115309 |
11 | 4242a8a915725 |
12 | 159907b348491 |
13 | 7500b3325a12 |
14 | 33a82473d149 |
15 | 17e421112774 |
hex | c098ab150ad |
13235121115309 has 2 divisors, whose sum is σ = 13235121115310. Its totient is φ = 13235121115308.
The previous prime is 13235121115301. The next prime is 13235121115351. The reversal of 13235121115309 is 90351112153231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7849959961284 + 5385161154025 = 2801778^2 + 2320595^2 .
It is a cyclic number.
It is not a de Polignac number, because 13235121115309 - 23 = 13235121115301 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13235121115301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6617560557654 + 6617560557655.
It is an arithmetic number, because the mean of its divisors is an integer number (6617560557655).
Almost surely, 213235121115309 is an apocalyptic number.
It is an amenable number.
13235121115309 is a deficient number, since it is larger than the sum of its proper divisors (1).
13235121115309 is an equidigital number, since it uses as much as digits as its factorization.
13235121115309 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24300, while the sum is 37.
The spelling of 13235121115309 in words is "thirteen trillion, two hundred thirty-five billion, one hundred twenty-one million, one hundred fifteen thousand, three hundred nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.090 sec. • engine limits •