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132354125200340 = 2256617706260017
BaseRepresentation
bin11110000110000000011000…
…100111011111101111010100
3122100121221010112220020010122
4132012000120213133233110
5114321442222022402330
61145254351251011112
736610161414562121
oct3606003047375724
9570557115806118
10132354125200340
113919908423543a
1212a17148899a98
1358b0c2c234504
142497d8c305748
151047c7b8315e5
hex7860189dfbd4

132354125200340 has 12 divisors (see below), whose sum is σ = 277943662920756. Its totient is φ = 52941650080128.

The previous prime is 132354125200307. The next prime is 132354125200351. The reversal of 132354125200340 is 43002521453231.

It can be written as a sum of positive squares in 2 ways, for example, as 83008389479236 + 49345735721104 = 9110894^2 + 7024652^2 .

It is a super-2 number, since 2×1323541252003402 (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 132354125200340.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3308853129989 + ... + 3308853130028.

It is an arithmetic number, because the mean of its divisors is an integer number (23161971910063).

Almost surely, 2132354125200340 is an apocalyptic number.

132354125200340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

132354125200340 is an abundant number, since it is smaller than the sum of its proper divisors (145589537720416).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

132354125200340 is a wasteful number, since it uses less digits than its factorization.

132354125200340 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6617706260026 (or 6617706260024 counting only the distinct ones).

The product of its (nonzero) digits is 86400, while the sum is 35.

Adding to 132354125200340 its reverse (43002521453231), we get a palindrome (175356646653571).

The spelling of 132354125200340 in words is "one hundred thirty-two trillion, three hundred fifty-four billion, one hundred twenty-five million, two hundred thousand, three hundred forty".

Divisors: 1 2 4 5 10 20 6617706260017 13235412520034 26470825040068 33088531300085 66177062600170 132354125200340