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132388030215391 is a prime number
BaseRepresentation
bin11110000110011111111101…
…100000110111010011011111
3122100202011122110011110002211
4132012133331200313103133
5114323021141213343031
61145322115501101251
736612501542500366
oct3606377540672337
9570664573143084
10132388030215391
11392014a2787035
1212a2182b557827
1358b41a36420b2
14249988721a7dd
151048ab31bbbb1
hex7867fd8374df

132388030215391 has 2 divisors, whose sum is σ = 132388030215392. Its totient is φ = 132388030215390.

The previous prime is 132388030215349. The next prime is 132388030215401. The reversal of 132388030215391 is 193512030883231.

It is a strong prime.

It is an emirp because it is prime and its reverse (193512030883231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 132388030215391 - 233 = 132379440280799 is a prime.

It is a super-2 number, since 2×1323880302153912 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132388030285391) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66194015107695 + 66194015107696.

It is an arithmetic number, because the mean of its divisors is an integer number (66194015107696).

Almost surely, 2132388030215391 is an apocalyptic number.

132388030215391 is a deficient number, since it is larger than the sum of its proper divisors (1).

132388030215391 is an equidigital number, since it uses as much as digits as its factorization.

132388030215391 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 933120, while the sum is 49.

The spelling of 132388030215391 in words is "one hundred thirty-two trillion, three hundred eighty-eight billion, thirty million, two hundred fifteen thousand, three hundred ninety-one".