Base | Representation |
---|---|
bin | 10011010001000011000… |
… | …111011000100000000111 |
3 | 11200120102011022012100001 |
4 | 103101003013120200013 |
5 | 133143000314423012 |
6 | 2452120503102131 |
7 | 164440233525424 |
oct | 23210307304007 |
9 | 4616364265301 |
10 | 1323975936007 |
11 | 47054999983a |
12 | 194718a41947 |
13 | 97b0941961a |
14 | 4811b91cd4b |
15 | 2468dc61357 |
hex | 134431d8807 |
1323975936007 has 2 divisors, whose sum is σ = 1323975936008. Its totient is φ = 1323975936006.
The previous prime is 1323975935899. The next prime is 1323975936029. The reversal of 1323975936007 is 7006395793231.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1323975936007 is a prime.
It is a super-2 number, since 2×13239759360072 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1323975936407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661987968003 + 661987968004.
It is an arithmetic number, because the mean of its divisors is an integer number (661987968004).
Almost surely, 21323975936007 is an apocalyptic number.
1323975936007 is a deficient number, since it is larger than the sum of its proper divisors (1).
1323975936007 is an equidigital number, since it uses as much as digits as its factorization.
1323975936007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6429780, while the sum is 55.
The spelling of 1323975936007 in words is "one trillion, three hundred twenty-three billion, nine hundred seventy-five million, nine hundred thirty-six thousand, seven".
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