Base | Representation |
---|---|
bin | 10011010001000100100… |
… | …011100111011100100111 |
3 | 11200120110211210120221201 |
4 | 103101010203213130213 |
5 | 133143023012130341 |
6 | 2452123125223331 |
7 | 164440646166526 |
oct | 23210443473447 |
9 | 4616424716851 |
10 | 1324000114471 |
11 | 470561603441 |
12 | 194724b61b47 |
13 | 97b114338c8 |
14 | 48120c144bd |
15 | 24690e3a331 |
hex | 134448e7727 |
1324000114471 has 2 divisors, whose sum is σ = 1324000114472. Its totient is φ = 1324000114470.
The previous prime is 1324000114391. The next prime is 1324000114483. The reversal of 1324000114471 is 1744110004231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1324000114471 - 211 = 1324000112423 is a prime.
It is a super-3 number, since 3×13240001144713 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1324000111471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 662000057235 + 662000057236.
It is an arithmetic number, because the mean of its divisors is an integer number (662000057236).
Almost surely, 21324000114471 is an apocalyptic number.
1324000114471 is a deficient number, since it is larger than the sum of its proper divisors (1).
1324000114471 is an equidigital number, since it uses as much as digits as its factorization.
1324000114471 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2688, while the sum is 28.
The spelling of 1324000114471 in words is "one trillion, three hundred twenty-four billion, one hundred fourteen thousand, four hundred seventy-one".
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