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13240004032243 is a prime number
BaseRepresentation
bin1100000010101010110110…
…1111001011011011110011
31201212201202122102121110201
43000222231233023123303
53213411012013012433
644054212431540031
72534362433252122
oct300525557133363
951781678377421
1013240004032243
11424506612346a
12159a00268a617
137506b0b3c291
1433ab69043ab9
1517e609b3ca7d
hexc0aadbcb6f3

13240004032243 has 2 divisors, whose sum is σ = 13240004032244. Its totient is φ = 13240004032242.

The previous prime is 13240004032219. The next prime is 13240004032271. The reversal of 13240004032243 is 34223040004231.

It is an a-pointer prime, because the next prime (13240004032271) can be obtained adding 13240004032243 to its sum of digits (28).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13240004032243 - 29 = 13240004031731 is a prime.

It is a super-2 number, since 2×132400040322432 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13240004032273) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6620002016121 + 6620002016122.

It is an arithmetic number, because the mean of its divisors is an integer number (6620002016122).

Almost surely, 213240004032243 is an apocalyptic number.

13240004032243 is a deficient number, since it is larger than the sum of its proper divisors (1).

13240004032243 is an equidigital number, since it uses as much as digits as its factorization.

13240004032243 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13824, while the sum is 28.

Adding to 13240004032243 its reverse (34223040004231), we get a palindrome (47463044036474).

The spelling of 13240004032243 in words is "thirteen trillion, two hundred forty billion, four million, thirty-two thousand, two hundred forty-three".