Base | Representation |
---|---|
bin | 111101101001110111… |
… | …0000111011001001111 |
3 | 110122202021000210010001 |
4 | 1323103232013121033 |
5 | 4132124140202432 |
6 | 140454011025131 |
7 | 12365010532654 |
oct | 1732356073117 |
9 | 418667023101 |
10 | 132401100367 |
11 | 51172a733a8 |
12 | 217b0a3b1a7 |
13 | c640487293 |
14 | 65a0333c2b |
15 | 369da559e7 |
hex | 1ed3b8764f |
132401100367 has 2 divisors, whose sum is σ = 132401100368. Its totient is φ = 132401100366.
The previous prime is 132401100341. The next prime is 132401100389. The reversal of 132401100367 is 763001104231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132401100367 - 231 = 130253616719 is a prime.
It is a super-3 number, since 3×1324011003673 (a number of 34 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132401100397) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66200550183 + 66200550184.
It is an arithmetic number, because the mean of its divisors is an integer number (66200550184).
Almost surely, 2132401100367 is an apocalyptic number.
132401100367 is a deficient number, since it is larger than the sum of its proper divisors (1).
132401100367 is an equidigital number, since it uses as much as digits as its factorization.
132401100367 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3024, while the sum is 28.
Adding to 132401100367 its reverse (763001104231), we get a palindrome (895402204598).
The spelling of 132401100367 in words is "one hundred thirty-two billion, four hundred one million, one hundred thousand, three hundred sixty-seven".
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