Base | Representation |
---|---|
bin | 11110000110101100010101… |
… | …001010111101110110100001 |
3 | 122100210102221002020112200121 |
4 | 132012230111022331312201 |
5 | 114323230341334430423 |
6 | 1145332153440320241 |
7 | 36613451640164320 |
oct | 3606542512756641 |
9 | 570712832215617 |
10 | 132401312030113 |
11 | 39207098a45015 |
12 | 12a24317613081 |
13 | 58b550c215469 |
14 | 249a3871840b7 |
15 | 10490de23945d |
hex | 786b152bdda1 |
132401312030113 has 16 divisors (see below), whose sum is σ = 156557072482560. Its totient is φ = 109557048484800.
The previous prime is 132401312030077. The next prime is 132401312030147. The reversal of 132401312030113 is 311030213104231.
It is not a de Polignac number, because 132401312030113 - 213 = 132401312021921 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (132401312030173) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 47606173 + ... + 50310538.
It is an arithmetic number, because the mean of its divisors is an integer number (9784817030160).
Almost surely, 2132401312030113 is an apocalyptic number.
It is an amenable number.
132401312030113 is a deficient number, since it is larger than the sum of its proper divisors (24155760452447).
132401312030113 is an equidigital number, since it uses as much as digits as its factorization.
132401312030113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 97923408.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 132401312030113 its reverse (311030213104231), we get a palindrome (443431525134344).
The spelling of 132401312030113 in words is "one hundred thirty-two trillion, four hundred one billion, three hundred twelve million, thirty thousand, one hundred thirteen".
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