Base | Representation |
---|---|
bin | 11110000110101100010101… |
… | …001010111101110111000011 |
3 | 122100210102221002020112201212 |
4 | 132012230111022331313003 |
5 | 114323230341334431042 |
6 | 1145332153440320335 |
7 | 36613451640164366 |
oct | 3606542512756703 |
9 | 570712832215655 |
10 | 132401312030147 |
11 | 39207098a45046 |
12 | 12a243176130ab |
13 | 58b550c215494 |
14 | 249a3871840dd |
15 | 10490de239482 |
hex | 786b152bddc3 |
132401312030147 has 2 divisors, whose sum is σ = 132401312030148. Its totient is φ = 132401312030146.
The previous prime is 132401312030077. The next prime is 132401312030173. The reversal of 132401312030147 is 741030213104231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132401312030147 - 28 = 132401312029891 is a prime.
It is not a weakly prime, because it can be changed into another prime (132401312030947) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66200656015073 + 66200656015074.
It is an arithmetic number, because the mean of its divisors is an integer number (66200656015074).
Almost surely, 2132401312030147 is an apocalyptic number.
132401312030147 is a deficient number, since it is larger than the sum of its proper divisors (1).
132401312030147 is an equidigital number, since it uses as much as digits as its factorization.
132401312030147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12096, while the sum is 32.
Adding to 132401312030147 its reverse (741030213104231), we get a palindrome (873431525134378).
The spelling of 132401312030147 in words is "one hundred thirty-two trillion, four hundred one billion, three hundred twelve million, thirty thousand, one hundred forty-seven".
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