Base | Representation |
---|---|
bin | 11110000110101100010101… |
… | …001010111101110110100000 |
3 | 122100210102221002020112200120 |
4 | 132012230111022331312200 |
5 | 114323230341334430422 |
6 | 1145332153440320240 |
7 | 36613451640164316 |
oct | 3606542512756640 |
9 | 570712832215616 |
10 | 132401312030112 |
11 | 39207098a45014 |
12 | 12a24317613080 |
13 | 58b550c215468 |
14 | 249a3871840b6 |
15 | 10490de23945c |
hex | 786b152bdda0 |
132401312030112 has 48 divisors (see below), whose sum is σ = 365845730614560. Its totient is φ = 41810940640512.
The previous prime is 132401312030077. The next prime is 132401312030147. The reversal of 132401312030112 is 211030213104231.
It is an interprime number because it is at equal distance from previous prime (132401312030077) and next prime (132401312030147).
It is a tau number, because it is divible by the number of its divisors (48).
It is a super-2 number, since 2×1324013120301122 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (24).
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 36294217483 + ... + 36294221130.
It is an arithmetic number, because the mean of its divisors is an integer number (7621786054470).
Almost surely, 2132401312030112 is an apocalyptic number.
132401312030112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
132401312030112 is an abundant number, since it is smaller than the sum of its proper divisors (233444418584448).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132401312030112 is a wasteful number, since it uses less digits than its factorization.
132401312030112 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 72588438645 (or 72588438637 counting only the distinct ones).
The product of its (nonzero) digits is 864, while the sum is 24.
Adding to 132401312030112 its reverse (211030213104231), we get a palindrome (343431525134343).
The spelling of 132401312030112 in words is "one hundred thirty-two trillion, four hundred one billion, three hundred twelve million, thirty thousand, one hundred twelve".
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