Base | Representation |
---|---|
bin | 111101101001111000… |
… | …1101111000100010101 |
3 | 110122202022210222210202 |
4 | 1323103301233010111 |
5 | 4132124411034201 |
6 | 140454043230245 |
7 | 12365021564354 |
oct | 1732361570425 |
9 | 418668728722 |
10 | 132402049301 |
11 | 51173561345 |
12 | 217b1218385 |
13 | c64072a192 |
14 | 65a04dd99b |
15 | 369db91c6b |
hex | 1ed3c6f115 |
132402049301 has 2 divisors, whose sum is σ = 132402049302. Its totient is φ = 132402049300.
The previous prime is 132402049291. The next prime is 132402049321. The reversal of 132402049301 is 103940204231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 80187514276 + 52214535025 = 283174^2 + 228505^2 .
It is an emirp because it is prime and its reverse (103940204231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 132402049301 - 26 = 132402049237 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132402049321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66201024650 + 66201024651.
It is an arithmetic number, because the mean of its divisors is an integer number (66201024651).
Almost surely, 2132402049301 is an apocalyptic number.
It is an amenable number.
132402049301 is a deficient number, since it is larger than the sum of its proper divisors (1).
132402049301 is an equidigital number, since it uses as much as digits as its factorization.
132402049301 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5184, while the sum is 29.
The spelling of 132402049301 in words is "one hundred thirty-two billion, four hundred two million, forty-nine thousand, three hundred one".
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