Base | Representation |
---|---|
bin | 1100000010101100000000… |
… | …1011010100101011110010 |
3 | 1201212202120012120010022122 |
4 | 3000223000023110223302 |
5 | 3213412130212300200 |
6 | 44054303242434242 |
7 | 2534403210656102 |
oct | 300530013245362 |
9 | 51782505503278 |
10 | 13240313400050 |
11 | 4245204816040 |
12 | 159a08a202982 |
13 | 75072cc69c59 |
14 | 33ab98175202 |
15 | 17e626d9c385 |
hex | c0ac02d4af2 |
13240313400050 has 48 divisors (see below), whose sum is σ = 26879418482112. Its totient is φ = 4812218750400.
The previous prime is 13240313399953. The next prime is 13240313400089. The reversal of 13240313400050 is 5000431304231.
It is a junction number, because it is equal to n+sod(n) for n = 13240313399992 and 13240313400019.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 5015534 + ... + 7185833.
It is an arithmetic number, because the mean of its divisors is an integer number (559987885044).
Almost surely, 213240313400050 is an apocalyptic number.
13240313400050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13240313400050 is an abundant number, since it is smaller than the sum of its proper divisors (13639105082062).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13240313400050 is a wasteful number, since it uses less digits than its factorization.
13240313400050 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12203363 (or 12203358 counting only the distinct ones).
The product of its (nonzero) digits is 4320, while the sum is 26.
Adding to 13240313400050 its reverse (5000431304231), we get a palindrome (18240744704281).
The spelling of 13240313400050 in words is "thirteen trillion, two hundred forty billion, three hundred thirteen million, four hundred thousand, fifty".
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