Base | Representation |
---|---|
bin | 11110000110101110010100… |
… | …100111101111111111101111 |
3 | 122100210122110002201222210201 |
4 | 132012232110213233333233 |
5 | 114323244231233010332 |
6 | 1145333145542414331 |
7 | 36613555633055614 |
oct | 3606562447577757 |
9 | 570718402658721 |
10 | 132403450281967 |
11 | 39207a95a2a307 |
12 | 12a248137313a7 |
13 | 58b5790207247 |
14 | 249a50b14a50b |
15 | 10491b6d0a5e7 |
hex | 786b949effef |
132403450281967 has 2 divisors, whose sum is σ = 132403450281968. Its totient is φ = 132403450281966.
The previous prime is 132403450281937. The next prime is 132403450282021. The reversal of 132403450281967 is 769182054304231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 132403450281967 - 219 = 132403449757679 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132403450281937) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66201725140983 + 66201725140984.
It is an arithmetic number, because the mean of its divisors is an integer number (66201725140984).
It is a 1-persistent number, because it is pandigital, but 2⋅132403450281967 = 264806900563934 is not.
Almost surely, 2132403450281967 is an apocalyptic number.
132403450281967 is a deficient number, since it is larger than the sum of its proper divisors (1).
132403450281967 is an equidigital number, since it uses as much as digits as its factorization.
132403450281967 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8709120, while the sum is 55.
The spelling of 132403450281967 in words is "one hundred thirty-two trillion, four hundred three billion, four hundred fifty million, two hundred eighty-one thousand, nine hundred sixty-seven".
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