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132403450281983 = 1301591101724313
BaseRepresentation
bin11110000110101110010100…
…100111101111111111111111
3122100210122110002201222211022
4132012232110213233333333
5114323244231233010413
61145333145542414355
736613555633055636
oct3606562447577777
9570718402658738
10132403450281983
1139207a95a2a321
1212a248137313bb
1358b579020725a
14249a50b14a51d
1510491b6d0a608
hex786b949effff

132403450281983 has 4 divisors (see below), whose sum is σ = 132403553307888. Its totient is φ = 132403347256080.

The previous prime is 132403450281967. The next prime is 132403450282021. The reversal of 132403450281983 is 389182054304231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 132403450281983 - 24 = 132403450281967 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132403450281083) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 49560566 + ... + 52163747.

It is an arithmetic number, because the mean of its divisors is an integer number (33100888326972).

Almost surely, 2132403450281983 is an apocalyptic number.

132403450281983 is a deficient number, since it is larger than the sum of its proper divisors (103025905).

132403450281983 is a wasteful number, since it uses less digits than its factorization.

132403450281983 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 103025904.

The product of its (nonzero) digits is 4976640, while the sum is 53.

The spelling of 132403450281983 in words is "one hundred thirty-two trillion, four hundred three billion, four hundred fifty million, two hundred eighty-one thousand, nine hundred eighty-three".

Divisors: 1 1301591 101724313 132403450281983