132404032001 has 2 divisors, whose sum is σ = 132404032002. Its totient is φ = 132404032000.

The previous prime is 132404031979. The next prime is 132404032003. The reversal of 132404032001 is 100230404231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 132169329601 + 234702400 = 363551^2 + 15320^2 .

It is a cyclic number.

It is not a de Polignac number, because 132404032001 - 2²² = 132399837697 is a prime.

Together with 132404032003, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (132404032003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66202016000 + 66202016001.

It is an arithmetic number, because the mean of its divisors is an integer number (66202016001).

Almost surely, 2^132404032001 is an apocalyptic number.

It is an amenable number.

132404032001 is a deficient number, since it is larger than the sum of its proper divisors (1).

132404032001 is an equidigital number, since it uses as much as digits as its factorization.

132404032001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 20.

Adding to 132404032001 its reverse (100230404231), we get a palindrome (232634436232).

The spelling of 132404032001 in words is "one hundred thirty-two billion, four hundred four million, thirty-two thousand, one".