Base | Representation |
---|---|
bin | 11000101010011000… |
… | …01111001100101011 |
3 | 1021011202012121100021 |
4 | 30111030033030223 |
5 | 204104022301103 |
6 | 10025500221311 |
7 | 646052544553 |
oct | 142514171453 |
9 | 37152177307 |
10 | 13240431403 |
11 | 56849730a1 |
12 | 269623a837 |
13 | 1330143cc4 |
14 | 8d8674163 |
15 | 5275e5bbd |
hex | 31530f32b |
13240431403 has 2 divisors, whose sum is σ = 13240431404. Its totient is φ = 13240431402.
The previous prime is 13240431397. The next prime is 13240431427. The reversal of 13240431403 is 30413404231.
13240431403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13240431403 - 225 = 13206876971 is a prime.
It is not a weakly prime, because it can be changed into another prime (13240431103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6620215701 + 6620215702.
It is an arithmetic number, because the mean of its divisors is an integer number (6620215702).
Almost surely, 213240431403 is an apocalyptic number.
13240431403 is a deficient number, since it is larger than the sum of its proper divisors (1).
13240431403 is an equidigital number, since it uses as much as digits as its factorization.
13240431403 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3456, while the sum is 25.
Adding to 13240431403 its reverse (30413404231), we get a palindrome (43653835634).
The spelling of 13240431403 in words is "thirteen billion, two hundred forty million, four hundred thirty-one thousand, four hundred three".
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