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132405023148113 is a prime number
BaseRepresentation
bin11110000110101111110010…
…010111110000100001010001
3122100210210111201100212112102
4132012233302113300201101
5114323310441411214423
61145334010010410145
736613642622155322
oct3606576227604121
9570723451325472
10132405023148113
1139208722858991
1212a24b92430955
1358b598102c781
14249a619dba449
151049259e49c28
hex786bf25f0851

132405023148113 has 2 divisors, whose sum is σ = 132405023148114. Its totient is φ = 132405023148112.

The previous prime is 132405023148103. The next prime is 132405023148137. The reversal of 132405023148113 is 311841320504231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 85440221718544 + 46964801429569 = 9243388^2 + 6853087^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132405023148113 is a prime.

It is not a weakly prime, because it can be changed into another prime (132405023148103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66202511574056 + 66202511574057.

It is an arithmetic number, because the mean of its divisors is an integer number (66202511574057).

Almost surely, 2132405023148113 is an apocalyptic number.

It is an amenable number.

132405023148113 is a deficient number, since it is larger than the sum of its proper divisors (1).

132405023148113 is an equidigital number, since it uses as much as digits as its factorization.

132405023148113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 69120, while the sum is 38.

The spelling of 132405023148113 in words is "one hundred thirty-two trillion, four hundred five billion, twenty-three million, one hundred forty-eight thousand, one hundred thirteen".