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1324051040317 is a prime number
BaseRepresentation
bin10011010001000111100…
…101111000100000111101
311200120121101121220002011
4103101013211320200331
5133143124031242232
62452132144531221
7164442135101425
oct23210745704075
94616541556064
101324051040317
11470588326815
1219473a020b11
1397b1bb54545
14481278ad485
1524695649547
hex1344797883d

1324051040317 has 2 divisors, whose sum is σ = 1324051040318. Its totient is φ = 1324051040316.

The previous prime is 1324051040303. The next prime is 1324051040371. The reversal of 1324051040317 is 7130401504231.

Together with next prime (1324051040371) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1278756134041 + 45294906276 = 1130821^2 + 212826^2 .

It is a cyclic number.

It is not a de Polignac number, because 1324051040317 - 219 = 1324050516029 is a prime.

It is a super-2 number, since 2×13240510403172 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1324051040617) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 662025520158 + 662025520159.

It is an arithmetic number, because the mean of its divisors is an integer number (662025520159).

Almost surely, 21324051040317 is an apocalyptic number.

It is an amenable number.

1324051040317 is a deficient number, since it is larger than the sum of its proper divisors (1).

1324051040317 is an equidigital number, since it uses as much as digits as its factorization.

1324051040317 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10080, while the sum is 31.

Adding to 1324051040317 its reverse (7130401504231), we get a palindrome (8454452544548).

The spelling of 1324051040317 in words is "one trillion, three hundred twenty-four billion, fifty-one million, forty thousand, three hundred seventeen".