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132409751381 is a prime number
BaseRepresentation
bin111101101010000111…
…1000111011101010101
3110122202212022022001222
41323110033013131111
54132133344021011
6140454520300125
712365144213405
oct1732417073525
9418685268058
10132409751381
1151177941aa6
12217b3911645
13c6421c5b1b
1465a1546805
15369e6b3ddb
hex1ed43c7755

132409751381 has 2 divisors, whose sum is σ = 132409751382. Its totient is φ = 132409751380.

The previous prime is 132409751333. The next prime is 132409751387. The reversal of 132409751381 is 183157904231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 132397738225 + 12013156 = 363865^2 + 3466^2 .

It is a cyclic number.

It is not a de Polignac number, because 132409751381 - 218 = 132409489237 is a prime.

It is a super-2 number, since 2×1324097513812 (a number of 23 digits) contains 22 as substring.

It is a Sophie Germain prime.

It is a Curzon number.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132409751387) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66204875690 + 66204875691.

It is an arithmetic number, because the mean of its divisors is an integer number (66204875691).

Almost surely, 2132409751381 is an apocalyptic number.

It is an amenable number.

132409751381 is a deficient number, since it is larger than the sum of its proper divisors (1).

132409751381 is an equidigital number, since it uses as much as digits as its factorization.

132409751381 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 181440, while the sum is 44.

The spelling of 132409751381 in words is "one hundred thirty-two billion, four hundred nine million, seven hundred fifty-one thousand, three hundred eighty-one".