Base | Representation |
---|---|
bin | 11000101010011100… |
… | …11011000110001111 |
3 | 1021011210021201101112 |
4 | 30111032123012033 |
5 | 204104144120211 |
6 | 10025520402235 |
7 | 646060452314 |
oct | 142516330617 |
9 | 37153251345 |
10 | 13241004431 |
11 | 5685224676 |
12 | 269647637b |
13 | 13302b4a85 |
14 | 8d8782d0b |
15 | 5276aa88b |
hex | 31539b18f |
13241004431 has 2 divisors, whose sum is σ = 13241004432. Its totient is φ = 13241004430.
The previous prime is 13241004409. The next prime is 13241004443. The reversal of 13241004431 is 13440014231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13241004431 - 210 = 13241003407 is a prime.
It is a super-2 number, since 2×132410044312 (a number of 21 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 13241004397 and 13241004406.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13241004401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6620502215 + 6620502216.
It is an arithmetic number, because the mean of its divisors is an integer number (6620502216).
Almost surely, 213241004431 is an apocalyptic number.
13241004431 is a deficient number, since it is larger than the sum of its proper divisors (1).
13241004431 is an equidigital number, since it uses as much as digits as its factorization.
13241004431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 13241004431 its reverse (13440014231), we get a palindrome (26681018662).
The spelling of 13241004431 in words is "thirteen billion, two hundred forty-one million, four thousand, four hundred thirty-one".
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