Base | Representation |
---|---|
bin | 111101101010001000… |
… | …1101011001101100101 |
3 | 110122202220120101011001 |
4 | 1323110101223031211 |
5 | 4132134032001432 |
6 | 140454542513301 |
7 | 12365153006041 |
oct | 1732421531545 |
9 | 418686511131 |
10 | 132410422117 |
11 | 5117825aa26 |
12 | 217b3b95831 |
13 | c64239c1cc |
14 | 65a167d021 |
15 | 369e7979e7 |
hex | 1ed446b365 |
132410422117 has 2 divisors, whose sum is σ = 132410422118. Its totient is φ = 132410422116.
The previous prime is 132410422091. The next prime is 132410422121. The reversal of 132410422117 is 711224014231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 131468607396 + 941814721 = 362586^2 + 30689^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132410422117 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (132410422717) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66205211058 + 66205211059.
It is an arithmetic number, because the mean of its divisors is an integer number (66205211059).
Almost surely, 2132410422117 is an apocalyptic number.
It is an amenable number.
132410422117 is a deficient number, since it is larger than the sum of its proper divisors (1).
132410422117 is an equidigital number, since it uses as much as digits as its factorization.
132410422117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2688, while the sum is 28.
Adding to 132410422117 its reverse (711224014231), we get a palindrome (843634436348).
The spelling of 132410422117 in words is "one hundred thirty-two billion, four hundred ten million, four hundred twenty-two thousand, one hundred seventeen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •