132410544353245 has 4 divisors (see below), whose sum is σ = 158892653223900. Its totient is φ = 105928435482592.

The previous prime is 132410544353221. The next prime is 132410544353251. The reversal of 132410544353245 is 542353445014231.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 63449843422681 + 68960700930564 = 7965541^2 + 8304258^2 .

It is a cyclic number.

It is not a de Polignac number, because 132410544353245 - 2¹⁹ = 132410543828957 is a prime.

It is a super-2 number, since 2×132410544353245² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 132410544353195 and 132410544353204.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13241054435320 + ... + 13241054435329.

It is an arithmetic number, because the mean of its divisors is an integer number (39723163305975).

Almost surely, 2^{132410544353245} is an apocalyptic number.

It is an amenable number.

132410544353245 is a deficient number, since it is larger than the sum of its proper divisors (26482108870655).

132410544353245 is an equidigital number, since it uses as much as digits as its factorization.

132410544353245 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 26482108870654.

The product of its (nonzero) digits is 3456000, while the sum is 46.

Adding to 132410544353245 its reverse (542353445014231), we get a palindrome (674763989367476).

The spelling of 132410544353245 in words is "one hundred thirty-two trillion, four hundred ten billion, five hundred forty-four million, three hundred fifty-three thousand, two hundred forty-five".