Base | Representation |
---|---|
bin | 11110000110110111010101… |
… | …100101011110111101111011 |
3 | 122100211120102201002210212002 |
4 | 132012313111211132331323 |
5 | 114323424042304012223 |
6 | 1145341430251411215 |
7 | 36614350542365615 |
oct | 3606672545367573 |
9 | 570746381083762 |
10 | 132413130141563 |
11 | 39211102a64077 |
12 | 12a26675453b0b |
13 | 58b667379460b |
14 | 249ab88975db5 |
15 | 1049581a2be28 |
hex | 786dd595ef7b |
132413130141563 has 2 divisors, whose sum is σ = 132413130141564. Its totient is φ = 132413130141562.
The previous prime is 132413130141541. The next prime is 132413130141569. The reversal of 132413130141563 is 365141031314231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132413130141563 - 26 = 132413130141499 is a prime.
It is not a weakly prime, because it can be changed into another prime (132413130141569) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66206565070781 + 66206565070782.
It is an arithmetic number, because the mean of its divisors is an integer number (66206565070782).
Almost surely, 2132413130141563 is an apocalyptic number.
132413130141563 is a deficient number, since it is larger than the sum of its proper divisors (1).
132413130141563 is an equidigital number, since it uses as much as digits as its factorization.
132413130141563 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 77760, while the sum is 38.
Adding to 132413130141563 its reverse (365141031314231), we get a palindrome (497554161455794).
The spelling of 132413130141563 in words is "one hundred thirty-two trillion, four hundred thirteen billion, one hundred thirty million, one hundred forty-one thousand, five hundred sixty-three".
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