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13241342230253 is a prime number
BaseRepresentation
bin1100000010101111110101…
…1111111111111011101101
31201212212012220111010000222
43000223331133333323231
53213421232102332003
644054553314101125
72534440542614054
oct300537537777355
951785186433028
1013241342230253
114245692540435
12159a31687a7a5
1375086515c817
1433ac54a6939b
1517e687375c38
hexc0afd7ffeed

13241342230253 has 2 divisors, whose sum is σ = 13241342230254. Its totient is φ = 13241342230252.

The previous prime is 13241342230213. The next prime is 13241342230271. The reversal of 13241342230253 is 35203224314231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9713924858089 + 3527417372164 = 3116717^2 + 1878142^2 .

It is a cyclic number.

It is not a de Polignac number, because 13241342230253 - 210 = 13241342229229 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13241342230213) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6620671115126 + 6620671115127.

It is an arithmetic number, because the mean of its divisors is an integer number (6620671115127).

Almost surely, 213241342230253 is an apocalyptic number.

It is an amenable number.

13241342230253 is a deficient number, since it is larger than the sum of its proper divisors (1).

13241342230253 is an equidigital number, since it uses as much as digits as its factorization.

13241342230253 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 103680, while the sum is 35.

Adding to 13241342230253 its reverse (35203224314231), we get a palindrome (48444566544484).

The spelling of 13241342230253 in words is "thirteen trillion, two hundred forty-one billion, three hundred forty-two million, two hundred thirty thousand, two hundred fifty-three".