132414012434342 has 4 divisors (see below), whose sum is σ = 198621018651516. Its totient is φ = 66207006217170.

The previous prime is 132414012434339. The next prime is 132414012434461. The reversal of 132414012434342 is 243434210414231.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 132414012434296 and 132414012434305.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33103503108584 + ... + 33103503108587.

It is an arithmetic number, because the mean of its divisors is an integer number (49655254662879).

Almost surely, 2^{132414012434342} is an apocalyptic number.

132414012434342 is a deficient number, since it is larger than the sum of its proper divisors (66207006217174).

132414012434342 is an equidigital number, since it uses as much as digits as its factorization.

132414012434342 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 66207006217173.

The product of its (nonzero) digits is 221184, while the sum is 38.

Adding to 132414012434342 its reverse (243434210414231), we get a palindrome (375848222848573).

The spelling of 132414012434342 in words is "one hundred thirty-two trillion, four hundred fourteen billion, twelve million, four hundred thirty-four thousand, three hundred forty-two".