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132414169 is a prime number
BaseRepresentation
bin1111110010001…
…11101011011001
3100020011100002111
413321013223121
5232344223134
621050032321
73165334066
oct771075331
9306140074
10132414169
11688207a8
12384186a1
13215825a4
141382bc6d
15b958c64
hex7e47ad9

132414169 has 2 divisors, whose sum is σ = 132414170. Its totient is φ = 132414168.

The previous prime is 132414167. The next prime is 132414179. The reversal of 132414169 is 961414231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 127418944 + 4995225 = 11288^2 + 2235^2 .

It is a cyclic number.

It is not a de Polignac number, because 132414169 - 21 = 132414167 is a prime.

It is a super-2 number, since 2×1324141692 = 35067024303921122, which contains 22 as substring.

Together with 132414167, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 132414169.

It is not a weakly prime, because it can be changed into another prime (132414167) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66207084 + 66207085.

It is an arithmetic number, because the mean of its divisors is an integer number (66207085).

Almost surely, 2132414169 is an apocalyptic number.

It is an amenable number.

132414169 is a deficient number, since it is larger than the sum of its proper divisors (1).

132414169 is an equidigital number, since it uses as much as digits as its factorization.

132414169 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5184, while the sum is 31.

The square root of 132414169 is about 11507.1355688547. The cubic root of 132414169 is about 509.6963064417.

The spelling of 132414169 in words is "one hundred thirty-two million, four hundred fourteen thousand, one hundred sixty-nine".