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13242014141 is a prime number
BaseRepresentation
bin11000101010100100…
…10001100110111101
31021011212012000110012
430111102101212331
5204104423423031
610025554153005
7646102156136
oct142522214675
937155160405
1013242014141
115685854244
122696882765
131330579535
148d8966c8d
15527809b2b
hex3154919bd

13242014141 has 2 divisors, whose sum is σ = 13242014142. Its totient is φ = 13242014140.

The previous prime is 13242014083. The next prime is 13242014161. The reversal of 13242014141 is 14141024231.

13242014141 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11408376100 + 1833638041 = 106810^2 + 42821^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13242014141 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13242014161) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6621007070 + 6621007071.

It is an arithmetic number, because the mean of its divisors is an integer number (6621007071).

Almost surely, 213242014141 is an apocalyptic number.

It is an amenable number.

13242014141 is a deficient number, since it is larger than the sum of its proper divisors (1).

13242014141 is an equidigital number, since it uses as much as digits as its factorization.

13242014141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 13242014141 its reverse (14141024231), we get a palindrome (27383038372).

The spelling of 13242014141 in words is "thirteen billion, two hundred forty-two million, fourteen thousand, one hundred forty-one".