Base | Representation |
---|---|
bin | 1100000010110011110111… |
… | …0011010110000011001010 |
3 | 1201212222000002110111110112 |
4 | 3000230331303112003022 |
5 | 3213430434241342102 |
6 | 44055252332514322 |
7 | 2534506352435645 |
oct | 300547563260312 |
9 | 51788002414415 |
10 | 13242421043402 |
11 | 42460964a4751 |
12 | 159a57801b9a2 |
13 | 7509a7802ab5 |
14 | 33ad18050a5c |
15 | 17e6ebe24252 |
hex | c0b3dcd60ca |
13242421043402 has 4 divisors (see below), whose sum is σ = 19863631565106. Its totient is φ = 6621210521700.
The previous prime is 13242421043389. The next prime is 13242421043413. The reversal of 13242421043402 is 20434012424231.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 12619396559641 + 623024483761 = 3552379^2 + 789319^2 .
It is a super-2 number, since 2×132424210434022 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3310605260849 + ... + 3310605260852.
Almost surely, 213242421043402 is an apocalyptic number.
13242421043402 is a deficient number, since it is larger than the sum of its proper divisors (6621210521704).
13242421043402 is an equidigital number, since it uses as much as digits as its factorization.
13242421043402 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6621210521703.
The product of its (nonzero) digits is 36864, while the sum is 32.
Adding to 13242421043402 its reverse (20434012424231), we get a palindrome (33676433467633).
The spelling of 13242421043402 in words is "thirteen trillion, two hundred forty-two billion, four hundred twenty-one million, forty-three thousand, four hundred two".
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