Base | Representation |
---|---|
bin | 1100000010110100010010… |
… | …0010110110011101100111 |
3 | 1201212222021222022102120201 |
4 | 3000231010202312131213 |
5 | 3213431202221111411 |
6 | 44055311453211331 |
7 | 2534512225061425 |
oct | 300550442663547 |
9 | 51788258272521 |
10 | 13242534160231 |
11 | 4246144335032 |
12 | 159a5a9a90b47 |
13 | 7509c5089a2c |
14 | 33ad29098115 |
15 | 17e706d1a3c1 |
hex | c0b448b6767 |
13242534160231 has 2 divisors, whose sum is σ = 13242534160232. Its totient is φ = 13242534160230.
The previous prime is 13242534160189. The next prime is 13242534160241. The reversal of 13242534160231 is 13206143524231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13242534160231 - 29 = 13242534159719 is a prime.
It is a super-2 number, since 2×132425341602312 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13242534160241) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6621267080115 + 6621267080116.
It is an arithmetic number, because the mean of its divisors is an integer number (6621267080116).
Almost surely, 213242534160231 is an apocalyptic number.
13242534160231 is a deficient number, since it is larger than the sum of its proper divisors (1).
13242534160231 is an equidigital number, since it uses as much as digits as its factorization.
13242534160231 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 103680, while the sum is 37.
Adding to 13242534160231 its reverse (13206143524231), we get a palindrome (26448677684462).
The spelling of 13242534160231 in words is "thirteen trillion, two hundred forty-two billion, five hundred thirty-four million, one hundred sixty thousand, two hundred thirty-one".
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