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13242554333 is a prime number
BaseRepresentation
bin11000101010101000…
…10101011111011101
31021011220012110110022
430111110111133131
5204110043214313
610030013521525
7646106566061
oct142524253735
937156173408
1013242554333
115686093088
122696aa32a5
131330708388
148d8a67aa1
155278b4c08
hex3155157dd

13242554333 has 2 divisors, whose sum is σ = 13242554334. Its totient is φ = 13242554332.

The previous prime is 13242554329. The next prime is 13242554389. The reversal of 13242554333 is 33345524231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10119756409 + 3122797924 = 100597^2 + 55882^2 .

It is an emirp because it is prime and its reverse (33345524231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13242554333 - 22 = 13242554329 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13242554293 and 13242554302.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13242524333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6621277166 + 6621277167.

It is an arithmetic number, because the mean of its divisors is an integer number (6621277167).

Almost surely, 213242554333 is an apocalyptic number.

It is an amenable number.

13242554333 is a deficient number, since it is larger than the sum of its proper divisors (1).

13242554333 is an equidigital number, since it uses as much as digits as its factorization.

13242554333 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 129600, while the sum is 35.

The spelling of 13242554333 in words is "thirteen billion, two hundred forty-two million, five hundred fifty-four thousand, three hundred thirty-three".