Base | Representation |
---|---|
bin | 100111011101111… |
… | …0011101101001011 |
3 | 10102021220110122001 |
4 | 1032323303231023 |
5 | 10203010114011 |
6 | 335224211431 |
7 | 44550242146 |
oct | 11673635513 |
9 | 3367813561 |
10 | 1324301131 |
11 | 61a59604a |
12 | 30b609b77 |
13 | 18149604a |
14 | c7c4905d |
15 | 7b3e07c1 |
hex | 4eef3b4b |
1324301131 has 2 divisors, whose sum is σ = 1324301132. Its totient is φ = 1324301130.
The previous prime is 1324301129. The next prime is 1324301137. The reversal of 1324301131 is 1311034231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1324301131 - 21 = 1324301129 is a prime.
It is a super-2 number, since 2×13243011312 = 3507546971135758322, which contains 22 as substring.
Together with 1324301129, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 1324301099 and 1324301108.
It is not a weakly prime, because it can be changed into another prime (1324301137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 662150565 + 662150566.
It is an arithmetic number, because the mean of its divisors is an integer number (662150566).
Almost surely, 21324301131 is an apocalyptic number.
1324301131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1324301131 is an equidigital number, since it uses as much as digits as its factorization.
1324301131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 19.
The square root of 1324301131 is about 36390.9484762351. The cubic root of 1324301131 is about 1098.1514768849.
Adding to 1324301131 its reverse (1311034231), we get a palindrome (2635335362).
The spelling of 1324301131 in words is "one billion, three hundred twenty-four million, three hundred one thousand, one hundred thirty-one".
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