Base | Representation |
---|---|
bin | 10011010001011000010… |
… | …111101110111000111111 |
3 | 11200121100000022201220212 |
4 | 103101120113232320333 |
5 | 133144213112343201 |
6 | 2452220122303035 |
7 | 164452123612523 |
oct | 23213027567077 |
9 | 4617300281825 |
10 | 1324332543551 |
11 | 470712217316 |
12 | 1947b8357a7b |
13 | 97b652771c4 |
14 | 48153029d83 |
15 | 246b0202abb |
hex | 134585eee3f |
1324332543551 has 2 divisors, whose sum is σ = 1324332543552. Its totient is φ = 1324332543550.
The previous prime is 1324332543533. The next prime is 1324332543563. The reversal of 1324332543551 is 1553452334231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1324332543551 - 26 = 1324332543487 is a prime.
It is a super-2 number, since 2×13243325435512 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1324332543499 and 1324332543508.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1324332540551) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 662166271775 + 662166271776.
It is an arithmetic number, because the mean of its divisors is an integer number (662166271776).
Almost surely, 21324332543551 is an apocalyptic number.
1324332543551 is a deficient number, since it is larger than the sum of its proper divisors (1).
1324332543551 is an equidigital number, since it uses as much as digits as its factorization.
1324332543551 is an evil number, because the sum of its binary digits is even.
The product of its digits is 648000, while the sum is 41.
Adding to 1324332543551 its reverse (1553452334231), we get a palindrome (2877784877782).
The spelling of 1324332543551 in words is "one trillion, three hundred twenty-four billion, three hundred thirty-two million, five hundred forty-three thousand, five hundred fifty-one".
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