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1324332543551 is a prime number
BaseRepresentation
bin10011010001011000010…
…111101110111000111111
311200121100000022201220212
4103101120113232320333
5133144213112343201
62452220122303035
7164452123612523
oct23213027567077
94617300281825
101324332543551
11470712217316
121947b8357a7b
1397b652771c4
1448153029d83
15246b0202abb
hex134585eee3f

1324332543551 has 2 divisors, whose sum is σ = 1324332543552. Its totient is φ = 1324332543550.

The previous prime is 1324332543533. The next prime is 1324332543563. The reversal of 1324332543551 is 1553452334231.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1324332543551 - 26 = 1324332543487 is a prime.

It is a super-2 number, since 2×13243325435512 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1324332543499 and 1324332543508.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1324332540551) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 662166271775 + 662166271776.

It is an arithmetic number, because the mean of its divisors is an integer number (662166271776).

Almost surely, 21324332543551 is an apocalyptic number.

1324332543551 is a deficient number, since it is larger than the sum of its proper divisors (1).

1324332543551 is an equidigital number, since it uses as much as digits as its factorization.

1324332543551 is an evil number, because the sum of its binary digits is even.

The product of its digits is 648000, while the sum is 41.

Adding to 1324332543551 its reverse (1553452334231), we get a palindrome (2877784877782).

The spelling of 1324332543551 in words is "one trillion, three hundred twenty-four billion, three hundred thirty-two million, five hundred forty-three thousand, five hundred fifty-one".