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13243344013 is a prime number
BaseRepresentation
bin11000101010101110…
…10110010010001101
31021011221200120200201
430111113112102031
5204110244002023
610030042453501
7646116365254
oct142527262215
937157616621
1013243344013
115686582409
122697204291
131330923943
148d8bd179b
155279bdbad
hex3155d648d

13243344013 has 2 divisors, whose sum is σ = 13243344014. Its totient is φ = 13243344012.

The previous prime is 13243344001. The next prime is 13243344067. The reversal of 13243344013 is 31044334231.

13243344013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9617136489 + 3626207524 = 98067^2 + 60218^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13243344013 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13243324013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6621672006 + 6621672007.

It is an arithmetic number, because the mean of its divisors is an integer number (6621672007).

Almost surely, 213243344013 is an apocalyptic number.

It is an amenable number.

13243344013 is a deficient number, since it is larger than the sum of its proper divisors (1).

13243344013 is an equidigital number, since it uses as much as digits as its factorization.

13243344013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10368, while the sum is 28.

Adding to 13243344013 its reverse (31044334231), we get a palindrome (44287678244).

The spelling of 13243344013 in words is "thirteen billion, two hundred forty-three million, three hundred forty-four thousand, thirteen".