Base | Representation |
---|---|
bin | 10011010001011100100… |
… | …001100000101001111111 |
3 | 11200121111212102102221022 |
4 | 103101130201200221333 |
5 | 133144333431344201 |
6 | 2452231051454355 |
7 | 164453631042062 |
oct | 23213441405177 |
9 | 4617455372838 |
10 | 1324402215551 |
11 | 470748583988 |
12 | 1948177573bb |
13 | 97b7682c63c |
14 | 4815c3a48d9 |
15 | 246b63b641b |
hex | 1345c860a7f |
1324402215551 has 2 divisors, whose sum is σ = 1324402215552. Its totient is φ = 1324402215550.
The previous prime is 1324402215431. The next prime is 1324402215607. The reversal of 1324402215551 is 1555122044231.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1324402215551 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1324402211551) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 662201107775 + 662201107776.
It is an arithmetic number, because the mean of its divisors is an integer number (662201107776).
Almost surely, 21324402215551 is an apocalyptic number.
1324402215551 is a deficient number, since it is larger than the sum of its proper divisors (1).
1324402215551 is an equidigital number, since it uses as much as digits as its factorization.
1324402215551 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48000, while the sum is 35.
Adding to 1324402215551 its reverse (1555122044231), we get a palindrome (2879524259782).
The spelling of 1324402215551 in words is "one trillion, three hundred twenty-four billion, four hundred two million, two hundred fifteen thousand, five hundred fifty-one".
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