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132442214833 is a prime number
BaseRepresentation
bin111101101011000101…
…0111101000110110001
3110122212010101121120001
41323112022331012301
54132220201333313
6140502040150001
712366020152135
oct1732612750661
9418763347501
10132442214833
11511941a52a5
1221802768301
13c648b51176
1465a59973c5
1536a2477add
hex1ed62bd1b1

132442214833 has 2 divisors, whose sum is σ = 132442214834. Its totient is φ = 132442214832.

The previous prime is 132442214831. The next prime is 132442214837. The reversal of 132442214833 is 338412244231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 115157065104 + 17285149729 = 339348^2 + 131473^2 .

It is a cyclic number.

It is not a de Polignac number, because 132442214833 - 21 = 132442214831 is a prime.

Together with 132442214831, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 132442214792 and 132442214801.

It is not a weakly prime, because it can be changed into another prime (132442214831) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66221107416 + 66221107417.

It is an arithmetic number, because the mean of its divisors is an integer number (66221107417).

Almost surely, 2132442214833 is an apocalyptic number.

It is an amenable number.

132442214833 is a deficient number, since it is larger than the sum of its proper divisors (1).

132442214833 is an equidigital number, since it uses as much as digits as its factorization.

132442214833 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 110592, while the sum is 37.

The spelling of 132442214833 in words is "one hundred thirty-two billion, four hundred forty-two million, two hundred fourteen thousand, eight hundred thirty-three".