Base | Representation |
---|---|
bin | 1100000010111010111010… |
… | …1000011111100101000011 |
3 | 1201220010220000102220000122 |
4 | 3000232232220133211003 |
5 | 3213443323342234014 |
6 | 44100204234010455 |
7 | 2534604306502403 |
oct | 300565650374503 |
9 | 51803800386018 |
10 | 13244314024259 |
11 | 4246977a9623a |
12 | 159aa05b76a2b |
13 | 750c19a49806 |
14 | 33b05760c803 |
15 | 17e7ad1e758e |
hex | c0baea1f943 |
13244314024259 has 2 divisors, whose sum is σ = 13244314024260. Its totient is φ = 13244314024258.
The previous prime is 13244314024199. The next prime is 13244314024261. The reversal of 13244314024259 is 95242041344231.
13244314024259 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (95242041344231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13244314024259 - 212 = 13244314020163 is a prime.
Together with 13244314024261, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (13244314024559) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6622157012129 + 6622157012130.
It is an arithmetic number, because the mean of its divisors is an integer number (6622157012130).
Almost surely, 213244314024259 is an apocalyptic number.
13244314024259 is a deficient number, since it is larger than the sum of its proper divisors (1).
13244314024259 is an equidigital number, since it uses as much as digits as its factorization.
13244314024259 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 829440, while the sum is 44.
The spelling of 13244314024259 in words is "thirteen trillion, two hundred forty-four billion, three hundred fourteen million, twenty-four thousand, two hundred fifty-nine".
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