Base | Representation |
---|---|
bin | 1100000010111101111011… |
… | …1110001000111011111011 |
3 | 1201220012222112102222112021 |
4 | 3000233132332020323323 |
5 | 3214002004000130201 |
6 | 44100420524055311 |
7 | 2534633354642032 |
oct | 300573676107373 |
9 | 51805875388467 |
10 | 13245125005051 |
11 | 42472538470a5 |
12 | 159abb1694537 |
13 | 751018a757c4 |
14 | 33b0d31d5719 |
15 | 17e8094dcea1 |
hex | c0bdef88efb |
13245125005051 has 2 divisors, whose sum is σ = 13245125005052. Its totient is φ = 13245125005050.
The previous prime is 13245125005043. The next prime is 13245125005067. The reversal of 13245125005051 is 15050052154231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13245125005051 - 23 = 13245125005043 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13245125004998 and 13245125005016.
It is not a weakly prime, because it can be changed into another prime (13245195005051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6622562502525 + 6622562502526.
It is an arithmetic number, because the mean of its divisors is an integer number (6622562502526).
Almost surely, 213245125005051 is an apocalyptic number.
13245125005051 is a deficient number, since it is larger than the sum of its proper divisors (1).
13245125005051 is an equidigital number, since it uses as much as digits as its factorization.
13245125005051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 30000, while the sum is 34.
Adding to 13245125005051 its reverse (15050052154231), we get a palindrome (28295177159282).
The spelling of 13245125005051 in words is "thirteen trillion, two hundred forty-five billion, one hundred twenty-five million, five thousand, fifty-one".
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