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13247119 is a prime number
BaseRepresentation
bin110010100010…
…001010001111
3220221000122001
4302202022033
511342401434
61151533131
7220412224
oct62421217
926830561
1013247119
117528836
12452a1a7
13298a842
141a8b94b
15126a114
hexca228f

13247119 has 2 divisors, whose sum is σ = 13247120. Its totient is φ = 13247118.

The previous prime is 13247111. The next prime is 13247159. The reversal of 13247119 is 91174231.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13247119 - 23 = 13247111 is a prime.

It is a super-2 number, since 2×132471192 = 350972323600322, which contains 22 as substring.

It is a Chen prime.

It is equal to p864271 and since 13247119 and 864271 have the same sum of digits, it is a Honaker prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13247111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6623559 + 6623560.

It is an arithmetic number, because the mean of its divisors is an integer number (6623560).

Almost surely, 213247119 is an apocalyptic number.

13247119 is a deficient number, since it is larger than the sum of its proper divisors (1).

13247119 is an equidigital number, since it uses as much as digits as its factorization.

13247119 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1512, while the sum is 28.

The square root of 13247119 is about 3639.6591873416. The cubic root of 13247119 is about 236.6140227637.

It can be divided in two parts, 13247 and 119, that added together give a triangular number (13366 = T163).

The spelling of 13247119 in words is "thirteen million, two hundred forty-seven thousand, one hundred nineteen".