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132472357875550 = 252711103790142281
BaseRepresentation
bin11110000111101110011111…
…110101010110111101011110
3122101001020022101112102210101
4132013232133311112331132
5114330411342104004200
61145424543331331314
736621545344000120
oct3607563765267536
9571036271472711
10132472357875550
1139234236523260
1212a36044750b3a
1358bc12222c364
14249d9a6a3d210
15104ad9b58526a
hex787b9fd56f5e

132472357875550 has 192 divisors, whose sum is σ = 310227339322368. Its totient is φ = 40883068800000.

The previous prime is 132472357875523. The next prime is 132472357875551. The reversal of 132472357875550 is 55578753274231.

It is a super-3 number, since 3×1324723578755503 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132472357875551) by changing a digit.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 3133120410 + ... + 3133162690.

It is an arithmetic number, because the mean of its divisors is an integer number (1615767392304).

Almost surely, 2132472357875550 is an apocalyptic number.

132472357875550 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

132472357875550 is an abundant number, since it is smaller than the sum of its proper divisors (177754981446818).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

132472357875550 is a wasteful number, since it uses less digits than its factorization.

132472357875550 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 50315 (or 50310 counting only the distinct ones).

The product of its (nonzero) digits is 246960000, while the sum is 64.

The spelling of 132472357875550 in words is "one hundred thirty-two trillion, four hundred seventy-two billion, three hundred fifty-seven million, eight hundred seventy-five thousand, five hundred fifty".