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13248119 is a prime number
BaseRepresentation
bin110010100010…
…011001110111
3220221002000002
4302202121313
511342414434
61151541515
7220415153
oct62423167
926832002
1013248119
117529565
12452a89b
13298b131
141a8c063
15126a57e
hexca2677

13248119 has 2 divisors, whose sum is σ = 13248120. Its totient is φ = 13248118.

The previous prime is 13248101. The next prime is 13248139. The reversal of 13248119 is 91184231.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13248119 - 28 = 13247863 is a prime.

It is a super-2 number, since 2×132481192 = 351025314076322, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 13248091 and 13248100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13248139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6624059 + 6624060.

It is an arithmetic number, because the mean of its divisors is an integer number (6624060).

Almost surely, 213248119 is an apocalyptic number.

13248119 is a deficient number, since it is larger than the sum of its proper divisors (1).

13248119 is an equidigital number, since it uses as much as digits as its factorization.

13248119 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1728, while the sum is 29.

The square root of 13248119 is about 3639.7965602489. The cubic root of 13248119 is about 236.6199764625.

The spelling of 13248119 in words is "thirteen million, two hundred forty-eight thousand, one hundred nineteen".