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132492541 is a prime number
BaseRepresentation
bin1111110010110…
…10110011111101
3100020022022121011
413321122303331
5232404230131
621051435221
73166111426
oct771326375
9306268534
10132492541
1168874675
1238455b11
13215ac16c
141384c64d
15b9720b1
hex7e5acfd

132492541 has 2 divisors, whose sum is σ = 132492542. Its totient is φ = 132492540.

The previous prime is 132492533. The next prime is 132492557. The reversal of 132492541 is 145294231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 131102500 + 1390041 = 11450^2 + 1179^2 .

It is an emirp because it is prime and its reverse (145294231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 132492541 - 23 = 132492533 is a prime.

It is a super-4 number, since 4×1324925414 (a number of 34 digits) contains 4444 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (132492511) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66246270 + 66246271.

It is an arithmetic number, because the mean of its divisors is an integer number (66246271).

Almost surely, 2132492541 is an apocalyptic number.

It is an amenable number.

132492541 is a deficient number, since it is larger than the sum of its proper divisors (1).

132492541 is an equidigital number, since it uses as much as digits as its factorization.

132492541 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 8640, while the sum is 31.

The square root of 132492541 is about 11510.5404304055. The cubic root of 132492541 is about 509.7968446265.

The spelling of 132492541 in words is "one hundred thirty-two million, four hundred ninety-two thousand, five hundred forty-one".