Base | Representation |
---|---|
bin | 10011010010000000011… |
… | …001100110110001011011 |
3 | 11200200001211000112001012 |
4 | 103102000121212301123 |
5 | 133202102023420402 |
6 | 2452410512444135 |
7 | 164504560135001 |
oct | 23220031466133 |
9 | 4620054015035 |
10 | 1325004123227 |
11 | 470a27315044 |
12 | 19496524964b |
13 | 97c41445625 |
14 | 481b82c6a71 |
15 | 246ee15e452 |
hex | 13480666c5b |
1325004123227 has 2 divisors, whose sum is σ = 1325004123228. Its totient is φ = 1325004123226.
The previous prime is 1325004123167. The next prime is 1325004123251. The reversal of 1325004123227 is 7223214005231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1325004123227 - 210 = 1325004122203 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1325004123193 and 1325004123202.
It is not a weakly prime, because it can be changed into another prime (1325004122227) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 662502061613 + 662502061614.
It is an arithmetic number, because the mean of its divisors is an integer number (662502061614).
Almost surely, 21325004123227 is an apocalyptic number.
1325004123227 is a deficient number, since it is larger than the sum of its proper divisors (1).
1325004123227 is an equidigital number, since it uses as much as digits as its factorization.
1325004123227 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20160, while the sum is 32.
Adding to 1325004123227 its reverse (7223214005231), we get a palindrome (8548218128458).
The spelling of 1325004123227 in words is "one trillion, three hundred twenty-five billion, four million, one hundred twenty-three thousand, two hundred twenty-seven".
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