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13250244124841 is a prime number
BaseRepresentation
bin1100000011010001000000…
…0110000010000010101001
31201220201012021222012201112
43000310100012002002221
53214042444443443331
644103024512400105
72535204254513363
oct300642006020251
951821167865645
1013250244124841
114249440414609
12159bb9bb46035
137516534b0779
1433b45b023d33
1517ea08b2432b
hexc0d101820a9

13250244124841 has 2 divisors, whose sum is σ = 13250244124842. Its totient is φ = 13250244124840.

The previous prime is 13250244124807. The next prime is 13250244124879. The reversal of 13250244124841 is 14842144205231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11405479840000 + 1844764284841 = 3377200^2 + 1358221^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13250244124841 is a prime.

It is not a weakly prime, because it can be changed into another prime (13250244121841) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6625122062420 + 6625122062421.

It is an arithmetic number, because the mean of its divisors is an integer number (6625122062421).

Almost surely, 213250244124841 is an apocalyptic number.

It is an amenable number.

13250244124841 is a deficient number, since it is larger than the sum of its proper divisors (1).

13250244124841 is an equidigital number, since it uses as much as digits as its factorization.

13250244124841 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 245760, while the sum is 41.

The spelling of 13250244124841 in words is "thirteen trillion, two hundred fifty billion, two hundred forty-four million, one hundred twenty-four thousand, eight hundred forty-one".