Base | Representation |
---|---|
bin | 1100000011010001000000… |
… | …0110000010000010000111 |
3 | 1201220201012021222012200021 |
4 | 3000310100012002002013 |
5 | 3214042444443443212 |
6 | 44103024512400011 |
7 | 2535204254513314 |
oct | 300642006020207 |
9 | 51821167865607 |
10 | 13250244124807 |
11 | 4249440414588 |
12 | 159bb9bb46007 |
13 | 7516534b0751 |
14 | 33b45b023d0b |
15 | 17ea08b24307 |
hex | c0d10182087 |
13250244124807 has 2 divisors, whose sum is σ = 13250244124808. Its totient is φ = 13250244124806.
The previous prime is 13250244124783. The next prime is 13250244124841. The reversal of 13250244124807 is 70842144205231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13250244124807 - 27 = 13250244124679 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13250244127807) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6625122062403 + 6625122062404.
It is an arithmetic number, because the mean of its divisors is an integer number (6625122062404).
Almost surely, 213250244124807 is an apocalyptic number.
13250244124807 is a deficient number, since it is larger than the sum of its proper divisors (1).
13250244124807 is an equidigital number, since it uses as much as digits as its factorization.
13250244124807 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 430080, while the sum is 43.
The spelling of 13250244124807 in words is "thirteen trillion, two hundred fifty billion, two hundred forty-four million, one hundred twenty-four thousand, eight hundred seven".
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