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13250244124807 is a prime number
BaseRepresentation
bin1100000011010001000000…
…0110000010000010000111
31201220201012021222012200021
43000310100012002002013
53214042444443443212
644103024512400011
72535204254513314
oct300642006020207
951821167865607
1013250244124807
114249440414588
12159bb9bb46007
137516534b0751
1433b45b023d0b
1517ea08b24307
hexc0d10182087

13250244124807 has 2 divisors, whose sum is σ = 13250244124808. Its totient is φ = 13250244124806.

The previous prime is 13250244124783. The next prime is 13250244124841. The reversal of 13250244124807 is 70842144205231.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13250244124807 - 27 = 13250244124679 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13250244127807) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6625122062403 + 6625122062404.

It is an arithmetic number, because the mean of its divisors is an integer number (6625122062404).

Almost surely, 213250244124807 is an apocalyptic number.

13250244124807 is a deficient number, since it is larger than the sum of its proper divisors (1).

13250244124807 is an equidigital number, since it uses as much as digits as its factorization.

13250244124807 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 430080, while the sum is 43.

The spelling of 13250244124807 in words is "thirteen trillion, two hundred fifty billion, two hundred forty-four million, one hundred twenty-four thousand, eight hundred seven".