Base | Representation |
---|---|
bin | 10011010010000010010… |
… | …000101000000000001001 |
3 | 11200200010222201122122012 |
4 | 103102002100220000021 |
5 | 133202133020322101 |
6 | 2452413545305305 |
7 | 164505416262416 |
oct | 23220220500011 |
9 | 4620128648565 |
10 | 1325035323401 |
11 | 470a42995209 |
12 | 194973795235 |
13 | 97c47a4a97a |
14 | 481bc4c910d |
15 | 24701c73bbb |
hex | 13482428009 |
1325035323401 has 2 divisors, whose sum is σ = 1325035323402. Its totient is φ = 1325035323400.
The previous prime is 1325035323377. The next prime is 1325035323487. The reversal of 1325035323401 is 1043235305231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1122423708025 + 202611615376 = 1059445^2 + 450124^2 .
It is a cyclic number.
It is not a de Polignac number, because 1325035323401 - 218 = 1325035061257 is a prime.
It is not a weakly prime, because it can be changed into another prime (1325035323301) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (11) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 662517661700 + 662517661701.
It is an arithmetic number, because the mean of its divisors is an integer number (662517661701).
Almost surely, 21325035323401 is an apocalyptic number.
It is an amenable number.
1325035323401 is a deficient number, since it is larger than the sum of its proper divisors (1).
1325035323401 is an equidigital number, since it uses as much as digits as its factorization.
1325035323401 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 32400, while the sum is 32.
The spelling of 1325035323401 in words is "one trillion, three hundred twenty-five billion, thirty-five million, three hundred twenty-three thousand, four hundred one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •